Answer by jfs for Time difference in seconds from numpy.timedelta64
To get number of seconds from numpy.timedelta64() object using numpy 1.7 experimental datetime API: seconds = dt / np.timedelta64(1, 's')
View ArticleAnswer by wim for Time difference in seconds from numpy.timedelta64
You can access it through the "wrapped" datetime item: >>> dt.item().total_seconds() 65.0 Explanation: here dt is an array scalar in numpy, which is a zero rank array or 0-dimensional array....
View ArticleTime difference in seconds from numpy.timedelta64
How to get time difference in seconds from numpy.timedelta64 variable? time1 = '2012-10-05 04:45:18' time2 = '2012-10-05 04:44:13' dt = np.datetime64(time1) - np.datetime64(time2) print dt 0:01:05 I'd...
View ArticleAnswer by Dema for Time difference in seconds from numpy.timedelta64
You can simply cast the value to the desired time unit using np.astype, as shown in the example:timedelta = np.datetime64('2011-07-18')-np.datetime64('2011-07-16')seconds =...
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